Same numbers, different values

Number Theory Level pending

k = 2 9 111. 1 k = ? \large \left\lfloor \sum_{k=2}^{9} 111.1_{k} \right \rfloor = ?

Input your answer in base 10.

Note: The subscripts denote the base of the number.


The answer is 337.

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1 solution

Efren Medallo
Jun 20, 2015

This is basically

k = 2 9 ( k 2 + k + 1 + 1 k ) \sum_{k=2}^{9} (k^2 + k + 1 + \frac{1}{k})

which sums up to 337.829 337.829 .

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