Sandwich divided by x x

Calculus Level 2

x cos ⁡ x ≤ g ( x ) ≤ sin ⁡ x \large x \cos x \leq g(x) \leq \sin x

Let g ( x ) g(x) satisfy the inequality above. Calculate lim ⁡ x → 0 g ( 3 x ) x \displaystyle \lim_{x\to0} \dfrac{g(3x)}x .


The answer is 3.

View wiki
Vinícius Zamariola by Vinícius Zamariola , 21, Brazil

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Relevant wiki: Squeeze Theorem

1. 2. Dividing by x 3. 4. Fundamental limit 5.

So, by squeeze theorem, the limit is 3

PS:I forgot to announce the limit in steps

3 Helpful 0 Interesting 0 Brilliant 0 Confused

I think you did a typo. *sin

Nanda Rahsyad - 5 years ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...