Sandy's theorem

Algebra Level 4

1 + 10 1 + 11 1 + 12 1 + 13 1 + ⋯ = ? \large \sqrt{1+10\sqrt{1+11\sqrt{1+12\sqrt{1+13\sqrt{1+\cdots } } } } } = \, ?


The answer is 11.

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Devarsh Wali by Devarsh Wali , 23, India

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2 solutions

Otto Bretscher
May 15, 2016

Ramanujan famously showed that 1 + x 1 + ( x + 1 ) 1 + . . . = x + 1 \sqrt{1+x\sqrt{1+(x+1)\sqrt{1+...}}}=x+1

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@Otto Bretscher Respected Sir, I have sent you an mail on your mail id which I got from internet regarding the verification of my theorem which is a general expansion of Sir Ramanujan's Theorem.Please if possible check the mail and reply soon. Regards

Devarsh Wali - 5 years, 1 month ago

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Thank you! I will do my best...

Otto Bretscher - 5 years, 1 month ago
Devarsh Wali
May 15, 2016

in the given below general expansion just put the value n=11

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