SAT Functions as Models

Algebra Level 2

If the current through a conductor decreases exponentially with time according to the equation I ( t ) = I 0 ( 5 4 ) t , I(t)=I_{0}\left(\frac{5}{4}\right)^{-t}, where I 0 = 64 I_{0}=64 mA is the initial current, how many seconds after t = 0 t=0 will the current be approximately 26 26 mA?

(A) One
(B) Two
(C) Three
(D) Four
(E) Five

A B C D E

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1 solution

Tatiana Georgieva Staff
Jan 28, 2015

Correct Answer: D

Solution 1:

Tip: Use a calculator.
We graph I ( t ) I(t) and check its value at t = 1 , 2 , 3 , 4 , t=1, 2, 3, 4, and 5. 5. When t = 4 t=4 s, I ( t ) = 26.2144 I(t)=26.2144 mA, as shown below. Therefore, choice (D) is the correct answer.

Solution 2:

Tip: Plug and check.
Tip: Use a calculator.
We plug each answer choice into the equation and select the one that yields I ( t ) 26 I(t) \approx 26 mA.

(A) If t = 1 t=1 s, I ( t ) = 64 ( 5 4 ) 1 = 51.2 I(t)=64\left(\frac{5}{4}\right)^{-1}=51.2 mA. Wrong.
(B) If t = 2 t=2 s, I ( t ) = 64 ( 5 4 ) 2 = 41 I(t)=64\left(\frac{5}{4}\right)^{-2}=41 mA. Wrong.
(C) If t = 3 t=3 s, I ( t ) = 64 ( 5 4 ) 3 = 32.8 I(t)=64\left(\frac{5}{4}\right)^{-3}=32.8 mA. Wrong.
(D) If t = 4 t=4 s, I ( t ) = 64 ( 5 4 ) 4 = 26.2 I(t)=64\left(\frac{5}{4}\right)^{-4}=26.2 mA. This is the correct answer.
(E) If t = 5 t=5 s, I ( t ) = 64 ( 5 4 ) 5 = 21 I(t)=64\left(\frac{5}{4}\right)^{-5}=21 mA. Wrong.



Incorrect Choices:

(A) , (B) , (C) , and (E)
Solution 1 eliminates these choices geometrically and Solution 2 eliminates them algebraically.

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