SAT Algebraic Manipulations

Algebra Level 1

If a ( b c ) = 32 a ( b-c) = 32 and a c = 8 ac = 8 , what is the value of a b ab ?

(A) 4 \ \ 4
(B) 8 \ \ 8
(C) 24 \ \ 24
(D) 32 \ \ 32
(E) 40 \ \ 40

A B C D E

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1 solution

Tatiana Georgieva Staff
Feb 1, 2015

Correct Answer: E

Solution:

Tip: When distributing, be careful with signs!
32 = a ( b c ) given 32 = a b a c use distributive property 32 + a c = a b add a c to both sides 32 + 8 = a b plug in a c = 8 40 = a b solve \begin{array}{r c l l} 32 &=& a ( b-c) &\quad \text{given}\\ 32 &=& ab - ac &\quad \text{use distributive property}\\ 32 + ac &=& ab &\quad \text{add}\ ac\ \text{to both sides}\\ 32 + 8 &=& ab &\quad \text{plug in}\ ac=8\\ 40 &=& ab &\quad \text{solve}\\ \end{array}



Incorrect Choices:

(A)
This wrong answer is the quotient of the two numbers that appear in the prompt.

(B)
Tip: Just because a number appears in the question doesn't mean it is the answer.
If a b = 8 ab = 8 , then a ( b c ) = a b a c = 8 8 = 0 a(b-c) = ab - ac = 8 - 8 = 0 , which is not equal to 32.

(C)
Tip: When distributing, be careful with signs!
You will get this wrong answer if you forget about the negative sign when distributing.
If you expand the given like this: a ( b c ) = a b + a c = 32 a (b-c) = ab \boxed{+} ac = 32 , you will obtain a b = 32 a c = 32 8 = 24 ab = 32 - ac = 32 - 8 = 24 .

(D)
Tip:Just because a number appears in the question doesn't mean it is the answer.
If a b = 32 ab = 32 , then a ( b c ) = a b a c = 32 8 = 24 a(b-c) = ab - ac = 32 - 8 = 24 , which is not equal to 32.

In Step 3, add 32 to both sides, instead of 32, shouldn't it be ac!

Danish Parvez - 7 months ago

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Thanks. I've updated the solution to reflect this.

I've marked this report as resolved.

Brilliant Mathematics Staff - 6 months, 2 weeks ago

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