SAT Change the Subject

Algebra Level 1

If a = 3 b 2 c a = 3b - 2c , which of the following is an expression for b b ?

(A) 3 b 2 c \ \ 3b - 2c

(B) a + 2 c \ \ a + 2c

(C) a + 3 c 2 \ \ \frac{a+3c}{2}

(D) a + 2 c 3 \ \ \frac{a+2c}{3}

(E) 3 b a 2 \ \frac{3b-a}{2}

A B C D E

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Tatiana Georgieva Staff
Feb 1, 2015

Correct Answer: D

Solution:

Tip: Follow order of operations.

3 b 2 c = a given ( 1 ) 3 b = a + 2 c add 2c to both sides ( 2 ) b = a + 2 c 3 divide by 3 on both sides ( 3 ) \begin{array} { l l l l } 3b - 2c & = a & \text{given} & (1) \\ 3b & = a + 2c & \text{add 2c to both sides} & (2)\\ b & = \frac{a+2c} {3} & \text{divide by 3 on both sides} & (3) \\ \end{array}



Incorrect Choices:

(A)
Tip: Just because a number appears in the question doesn’t mean it is the answer.
This is just the expression for a a .

(B)
Tip: Read the entire question carefully.
If you stop at step ( 2 ) , (2), you will obtain a + 2 c a + 2c . However, this equals 3 b 3b , not b b .

(C)
Tip: Read the entire question carefully.
If you swap the coefficients of b b and c c like this, a = 2 b 3 c a = \boxed{2}b - \boxed{3} c , then solving for b b will give b = a + 3 c 2 . b = \frac{ a + 3c } { 2 } .

(E)
Tip: Read the entire question carefully.
If you solve for c c , you will obtain this wrong answer.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...