Maria has 4 hats, 2 jackets, and 2 shawls. To go out, she needs a hat, a jacket, and a shawl. In how many different ways can she combine her outerwear?
(A)
(B)
(C)
(D)
(E)
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Correct Answer: D
Solution 1:
Tip: If there are n ways for an event to happen and m ways for another event to happen, then the number of ways for both events to happen is m ⋅ n .
By the fundamental counting principle, she can combine her outerwear in 4 ⋅ 2 ⋅ 2 = 1 6 ways.
Solution 2:
We could also create a tree diagram, where each branch represents a single choice. We count the number of branches to find out how many combinations there are.
In this case that number is 16.
Incorrect Choices:
(A)
This is how many hats Maria has.
(B)
You will get this wrong choice if you apply the rule of sum instead of the rule of product and get 2+2+4 = 8, or if you find how many hat-jacket or hat-shawl combinations there are.
(C) and (E)
These answers are just offered to confuse you.