SAT Lines

Geometry Level 1

In the diagram above, points A A and B B have coordinates a a and b , b, such that b > a . b>a. If M M is the midpoint of segment A B , \overline{AB}, and M M has the coordinate x , x, all of the following are true EXCEPT:

(A) A M = 1 2 A B \ \ AM = \frac{1}{2}AB
(B) M B = b x \ \ MB = b-x
(C) A M M B \ \ \overline{AM} \cong \overline{MB}
(D) 2 x = a + b \ \ 2x = a+b
(E) x = 2 b a \ \ x = 2b-a

A B C D E

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1 solution

Tatiana Georgieva Staff
Feb 18, 2015

Correct Answer: E

Solution:

Tip: The midpoint of a segment divides it in half.
We show why all of the answer choices are true, except choice (E):

(A) If M M is the midpoint of segment A B , \overline{AB}, then A M = M B = 1 2 A B . AM= MB = \frac{1}{2}AB. Therefore this statement is true.

(B) Recall that if m m and n n are on a number line, and m < n m<n , then the distance between m m and n n is n m . n-m. In this case, b > x b>x and therefore M B = b x . MB = b-x. This statement is true.

(C) By definition, the midpoint divides a segment into two congruent segments. If M M is the midpoint of A B , \overline{AB}, as is the case here, then A M M B . \overline{AM} \cong \overline{MB}.

(D) A M = a x AM = a-x and B M = b x . BM = b-x. By the definition of a midpoint, A M M B \overline{AM} \cong \overline{MB} or A M = M B . AM = MB. It follows then that a x = b x , a-x = b-x, and re-arranging, we obtain 2 x = a + b . 2x =a+b. Therefore (D) is also true.

(E) Following the reasoning in (D), we conclude that x = a + b 2 2 b a . x = \frac{a+b}{2} \neq 2b-a. Option (E) is false, and it is the correct answer.



Incorrect Choices:

(A) , (B) , (C) , and (D)
The solution explains why these choices are wrong.

how can a-x=b-x be 2x=a+b? Wont the x be cancelled as it was the same sign. When we do change it, it will be a-b= -x+x which is a-b=0?

sharvaree bhalerao - 9 months, 2 weeks ago

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