SAT Math IV

Algebra Level 2

In a group of 300 mice, 75% are male and 20% are albino. What is the greatest number of mice in the group that could be both female and not albino?

60 240 225 75

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2 solutions

John M.
Aug 27, 2014

Out of 300 mice, if 75% are male, 25% must be female, so translate: 25 100 × 300 = 75 \frac{25}{100}\times 300=75 females.

Eliminate D and E, because there are no more than 75 females of any sort. Because 20% of the mice are albino, and 25% of the mice are female, both groups are small enough not to overlap at all.

There are 80% non-albino mice, so 80 100 × 300 = 240 \frac{80}{100}\times 300=240 non-albino mice, so all 75 \boxed{75} females could be non-albinos.


Solution Credit: The Princeton Review

Over-rated problem!

Kartik Sharma - 6 years, 9 months ago
Mohammad Saleem
Mar 13, 2015

This is an explanatory answer and not one based on efficiency.

Basically, you have 300 mice right? It's asking for females and not albino right?

To find the number of females: 75%(male) of 300(total) = 225 male mice. 300-225 = 75 female mice So, we have ATLEAST 75 mice that are in this category. Now on to restricting this group to not albino .

Well, since we have 20% of the whole population of mice as albino, that means that 60 mice are albino, right? For all we know, those 60 could all be males -->

75 is the answer

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