Set X consists of twelve numbers. The average (arithmetic mean) of the first six numbers is 15. The sum of the last six numbers is 24. What is the average of all twelve numbers in set X?
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Use an average every time the question uses the word average . An average pie looks like this:
A circle that is divided into three sections:
In this case we end up with the following average pies that use the information in the question (1,2,3 - as in above) (draw them so you can see them):
First Six: (90,6,15)
+
Last Six: (24,6,4)
=
(114,12,95)
We need an average pie for the first six numbers: the six numbers' average is 15, so the total of those six numbers is 1 5 × 6 = 9 0 The last six have an average of 4 , so the total of those six numbers is 4 × 6 = 2 4 . Now take the two totals and add them together for the final mention of the word average . The total for all 12 numbers is 114, so to find the average, divide 114 by 12, which gives 9 . 5 .
(You could also reduce the fraction 1 2 1 1 4 , since the numberator and denominator are both divisible by 6, to 2 1 9 = 9 . 5
I feel a much more simpler method would be this:
You have 12 numbers. To get the average you must add up all the numbers.
A) The first part gives you the average of the first 6 numbers, which is 15. So 15*6 = 90 . So we know if you add up the first 6 numbers, you will get 90 .
B) The sum of the last 6 numbers is given 24
C) Add the two parts ( 24+90 = 114 ) and divide it by the total number of numbers. 114/12 = 9.5
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The average of the last six numbers is 4 because 24/6=4. So, the total average is the average of the average of the first and the average of the last six numbers. So, it's (15+4)/2= 19/2=9.5