Parallel Lines

Geometry Level 1

Given that all three of the horizontal lines are parallel, what is the measurement of the red angle in degrees?

Note : The diagram is not drawn to scale.

30 135 150 210 240

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3 solutions

Discussions for this problem are now closed

Justin Ruaya
Mar 8, 2016

Relevant wiki: SAT Lines and Angles

AHh I was so used to the right angle. I was thinking the answer was 120 x'D so i was like maybe 135 LOL

Zachary Provenzano - 5 years, 2 months ago

i don't know why it deceived me to think that the top triangle have a 90 - 60 - 60 angles :D :D

Mena Sameh - 5 years, 3 months ago

thank you so much.

Christine Conlas - 5 years, 3 months ago
Tatiana Georgieva Staff
Feb 18, 2015

Solution 1:

Tip: Know the Properties of Parallel Lines.
Tip: An exterior angle in a triangle equals the sum of the two nonadjacent interior angles.
Refer to the diagram below.

x x and a a are alternate interior angles. Therefore x = a . x=a. The two transversals and line p p form a triangle, shown in the figure in green. We know that in a triangle, the measure of an exterior angle equals the sum of the measures of the two nonadjacent interior angles. Therefore, y = a + 90 = x + 90 , y = a + 90 = x + 90, which is choice (B).

Solution 2:

Tip: Know the Properties of Parallel Lines.
Tip: The two acute angles in a right triangle are complementary.
Refer to the diagram below.

x x and a a are vertical angles. Therefore x = a . x=a.

a a and b b are the acute angles in a right triangle, shown in green, and therefore add to 9 0 . 90^\circ. It follows that b = 90 a . b=90-a.

y y and b b are same-side exterior angles. Same-side exterior angles are supplementary and therefore y + b = 180. y + b =180. We solve this equation:

y + b = 180 same-side exterior angles are supplementary y = 180 b y = 180 ( 90 a ) substitute b = 90 a \ y = 180 90 + a y = 90 + a y = 90 + x \begin{array}{r c l l} y + b &=& 180 &\quad \text{same-side exterior angles}\\ &&&\quad \text{are supplementary}\\ y &=& 180-b &\\ y &=& 180 - (90-a) &\quad \text{substitute}\ b=90-a\\\ y &=& 180 - 90 +a &\\ y &=& 90 +a &\\ y &=& 90+x &\\ \end{array}

Right, but the image is wrong. It suggests the idea that the triangle is isosceles. In that case, the angle you claim to be 60°, would be 45°.

Domenico Franceschelli - 5 years, 4 months ago

The image is not wrong. It may look like an isosceles triangle but it's not.

The 60 ° 60° clearly indicates that it's not an isosceles triangle.

Edit: Whoever downvoted my comment should indicate and explain where I could be wrong at, not just downvoting and running away. You can't learn math this way.

Kenneth Choo - 5 years, 4 months ago

there is a vertically opposite angle = 60 and if we consider the small right triangle we get the third side which is 30, the angle below it is also 30 ( corresponding angles ) now we know that a straight line = 180 degrees therefore 30+ red angle = 180 degrees, red angle = 150 degrees

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