For all positive integers k , ◊ k is the sum of all of k 's factors. How many factors does ◊ 2 0 − ◊ 1 0 have?
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Another way to solve this is to notice that 1 0 is a factor of 2 0 . So we can interpret ◊ 2 0 − ◊ 1 0 as the sum of factor(s) of 2 0 but not a factor of 1 0 . By inspection, we can see that 4 and 2 0 are the only numbers that satisfies the criteria. Thus ◊ 2 0 − ◊ 1 0 = 4 + 2 0 = 2 4 = 2 3 × 3 . With the number of factors to be ( 3 + 1 ) × ( 1 + 1 ) = 8 .
20 - 1,2,4,5,10,20
10 - 1,2,5,10
1+2+4+5+10+20=42
1+2+5+10=18
42-18=24
24 - 1,2,3,4,6,8,12,24
8 factors
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Correct Answer: 8
Solution:
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The factors of 20 are 1, 2, 4, 5, 10, and 20. Therefore,
◊ 2 0 = 1 + 2 + 4 + 5 + 1 0 + 2 0 = 4 2 .
The factors of 10 are 1, 2, 5, and 10. Therefore,
◊ 1 0 = 1 + 2 + 5 + 1 0 = 1 8
and
◊ 2 0 − ◊ 1 0 = 4 2 − 1 8 = 2 4 .
24 has 8 factors: 1, 2, 3, 4, 6, 8, 12, and 24. So, the answer is 8.
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If you got this problem wrong, you should review SAT Newly Defined Functions and SAT Factors, Divisibility, and Remainders .