Saturn V rocket

The largest rocket ever launched was the Saturn V, which carried missions to the moon. The total mass of the rocket and payload was 2,800,000 kg. What was the minimum thrust in Newtons the engines needed to provide to launch the rocket?

Details and assumptions

  • The acceleration of gravity is 9.8 m/s 2 -9.8\text{ m/s}^2 .


The answer is 2.74E+7.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

6 solutions

Edward Jiang
Sep 14, 2013

Using F = m a F=ma , we have F = 2800000 × 9.8 = 2.744 × 1 0 7 F=2800000\times 9.8=2.744\times 10^7

Jess Smith
Sep 8, 2013

The rocket has to apply a force equal to the gravitational force acting on it, so

Force of gravity = mass * acceleration = 2 , 800 , 000 k g × ( 9.8 ) m / s 2 = 2,800,000 \ kg \times (9.8) \ m/s^2 = 2.74E+7 Newtons

Vikas Mali
Sep 9, 2013

the mass of rocket is 2,800,000 and the g=-9.8 . so the force is
F=mg, F=2800000*9.8=2.74E+7

Gravity force is m g, if rocket want to fly it needs to get acceleration a=9.81m/s2^, so 2nd Newton's law says F=m a=9.8m/s^2*2.800.000kg=2.74E+7N

Kauan Santos
Sep 13, 2013

F = m.a F = 2.800.000 . 9,8 = 2.74.10^7

Russell Few
Sep 8, 2013

The only force that the rocket needs to overcome is the force of the gravity of the Earth.

The force of gravity of Earth, by F = m a F=ma , is 2 , 800 , 000 k g 9.8 m s 2 = 27 , 400 , 000 N 2,800,000 kg \cdot 9.8 \frac{m}{s^2}=27,400,000 N . The rocket has to have a thrust at least this. Thus, the minimum thrust the engines needed to provide to launch the rocket is 27 , 400 , 000 N = 2.74 1 0 7 N 27,400,000N=\boxed{2.74 \cdot 10^7}N .

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...