Saurav's Square #4
Let X be a smallest 9 digit number such that last 9 digits of the square of number X is the number (X) itself. Find the digit sum of the digit sum of number X.
For eg. Let the number be 789. so, the digit sum of the digit sum of 789 : 7+8+9 = 24 2+4 = 6. So, the answer will be 6.
The answer is 8.
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1 solution
The number is 212890625. So, the digit sum of the digit sum of 212890625 is 8.