Scampering mouse

Since east and north are perpendicular, the mouse runs $\sqrt{3^2+4^2}=\sqrt{25}=5$ meters. Since velocity is $\dfrac{distance}{time}$ , the average velocity is $\dfrac{5\ meters}{5\ seconds}=\boxed{1}\dfrac{m}{s}$

In order to solve this problem, we need to find out the distance covered by the mouse. As it runs $3$ m eaat and $4$ m, the total distance covered by it can be found by using Pythagoras theorem. he runs a total of $\sqrt{3^{2}+4^{2}}$ $=\sqrt{9+16}$ $=\sqrt{25}$ $=5 m$ So, the magnitude of the mouse's average velocity $=\frac{Displacement}{Time}$ $=\frac{5}{5}$ $=\boxed{1 ms^{-1}}$

Use Pythagore 's law : x = \sqrt{3^2 + 4^2 } = 5 (m ) v =\frac {s}{t} = \frac {5}{5} = 1

The length covered by the mouse = $\sqrt{3^2 + 4^2} = 5$ . So, the average velocity = $\dfrac{5}{5} = \color{#69047E}{\boxed{1}}m/s$ .

As velocity is a vector quantity,so,its formula is displacement/time.Displacement is the shortest distance between two points in a specific direction,so according to pythogoras theorem,the displacement between two points is 5.Thus ,the velocity is 5/5=1

Average=3+4/2=3.5 Time given=5s To find Magnitude=average/time(s) Magnitude=3.5/5s=0.7 nearly equal to 1=1ans

by phythagoras theorem,you will get s=hypotenuse,where s^2=3^2 + 4^2,s=5m,

then by applying v=s/t=5m/5s=1m/s...

the net displacement of the mouse is sqrt( 3sqr + 4sqr ) = 5 metres the time taken is 5 seconds. thus velocity of mouse is 5m/5s= 1 m/s

H² = c'² + c"² \* H² = 3²+4² \* H=5m \* v=s/t \* v= 5\5 \* v=1

net displacement=sqrt( 3^2+4^2)=5 . avg velocity = total displacement/total time= 5/5=1 m/s.

The mouse forms two sides of a right-angled triangle as it goes 3 m east and then forming a right-angle, turns to go 4 m north. Now, velocity = Displacement/time Hence the displacement = Average distance which can also be shown as the hypotenuse of the right - angled triangle formed. Hypotenuse = (By Pythagoras theorem) Square root of (3^2 + 5^2) which happens to be = 5 Hence, Displacement = 5 m and Time taken = 5 s (Given) So, velocity = 5/5 = 1