Schematic for a function

Which of the following functions is implemented by the above schematic?

F 2 = x ˉ z + x y ˉ F_{2} = \bar { x } \cdot z+x \cdot \bar { y } F 2 = y ˉ z + y x ˉ F_{2} = \bar { y } \cdot z+y \cdot \bar { x } F 2 = x + y ˉ z F_{2} = x+\bar { y } \cdot z F 2 = x ˉ + y z F_{2} = \bar { x } +y\cdot z

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5 solutions

Heres Junqueira
May 3, 2014

F2 = (!x!yz)+(!xyz)+(x!y)

Using the karnaugh's map or simplifying by boole's algebra

F2 = !xz + x!y

Deepjyoti Nath
May 4, 2014

In the question F2 becomes F2=x!y!z+x!yz+xy! F2=x!z(y!+y)+xy! F2=x!z+xy! since y!+y=1

(x'y'z)+(x'yz)+(xy')=F2, then by using the karnaugh's map or the knowledge on simplifying functions using Boolean algebra we arrive in this equation

(xy')+(x'z)=F2

Tejas Shinde
May 10, 2014

just substitute and find F2 and match it with the given options

Shaksham Kapoor
May 6, 2014

simply applying the concepts of boolean laws...........

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