Schwarzschild

Level pending

The Schwarzschild radius is the radius at which the escape velocity of a spherically symmetric, non-rotating body is the speed of light. The Schwarzschild radius of the human body can be expressed to three significant figures as $\overline{abc} \times 10^{-27} \text{m}$ . Determine the value of $\overline{abc}$ given that the human body is made into the shape of a sphere and that the average mass of the human body is $70\text{kg}$ .

Image Credit: David Darling

The answer is 104.

1 solution

Sharky Kesa
Dec 28, 2013

By inputting the equation to get Schwarzschild radius $r_s = \frac {2Gm}{c^2}$ (where $r_s$ is the Schwarzschild radius, $G$ is the gravitational constant, $m$ is the mass and $c$ is the speed of light) into the question, you get $2 \times 6.67 \times 10^{-11} = \frac {70}{(3 \times 10^8)^2}$ which equals to $104 \times 10^{-27}$ metres.

Your equation stating that $2 \times 6.67 \times 10^{-11} = \frac{70}{(3 \times 10^{8})^{2}}$ isn't correct. There is no variable to solve for and the two sides are not equivalent to each other. You must have made a transfer error seeing that you got the right answer.

Cole Coupland - 7 years, 5 months ago

Schwarzschild

The answer is 104.

1 solution

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