The figure shows the most efficient packing of six identical circles in a square of side length .
Radius of each circle is .
Find .
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From the picture below:
2 r + 2 a = 1 ⇒ a = 2 1 − 2 r
2 r + 3 b = 1 ⇒ b = 3 1 − 2 r
a 2 + b 2 = ( 2 r ) 2
( 2 1 − 2 r ) 2 + ( 3 1 − 2 r ) 2 = 4 r 2
3 6 1 3 ( 1 − 2 r ) 2 = 4 r 2
Simplify and solve for r
r = 4 6 6 1 3 − 1 3 or r = 4 6 − 6 1 3 − 1 3 N e g l e c t e d
then A = 1 3