Second base

Let b , B 12 b, B \geq 12 .

If B B expressed in base b b is 1 2 b 12_b ,

and a number x x expressed in base B B is x = 12 3 B x = 123_B ,

then what is the value of x x expressed in base b b ?


Notes and assumptions

We follow the custom of using letters to represent digits greater than 9. Thus, A = 1 0 10 \mathrm{A} = 10_{10} , B = 1 1 10 \mathrm{B} = 11_{10} , C = 1 2 10 \mathrm{C} = 12_{10} , and so on.

Note that the variable B B in this problem is not the same as the digit B \mathrm{B} .

It depends on the value of b b . x = 17 1 b x = 171_b x = 16 B b x = 16\mathrm{B}_b

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1 solution

Arjen Vreugdenhil
Sep 22, 2017

Since x = B 2 + 2 B + 3 x = B^2 + 2B + 3 and B = b + 2 B = b + 2 , we have x = ( b + 2 ) 2 + 2 ( b + 2 ) + 3 = ( b 2 + 4 b + 4 ) + ( 2 b + 4 ) + 3 = b 2 + 6 b + 11. x = (b+2)^2 + 2(b+2) + 3 = (b^2 + 4b + 4) + (2b + 4) + 3 = b^2 + 6b + 11. Because we know b 12 b \geq 12 , digits are available with values up to B = 11 \mathrm B = 11 . Therefore the result is x = 16 B b , x = 16\mathrm{B}_b, independent of the value of b b .

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