If a car with 0 m/s initial velocity and 4 m/s^2 uniform acceleration, passes 2 m at it's 3rd second. What is the displacement at 4th second of it?
Enter the answer without unit.
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As we know that the -th second formula is Sth=ut + 1/2a(2t-1).
So we can calculate by above given information.
There, initial velocity, u=0 m/s time(th), t=4 acceleration, a=4 m/s^2 displacement, S= ?
so, S= 0 m/s 4 + 1/2 4 m/s^2(2 4-1) =2 7 m =14 m