A number theory problem by Yash Singhal

@ first U add (0) to (2) then add (1)& Add (3) @ the end . as we see if the number ends with (0) or (2) ,it is not prime . when U add (1) to the number it becomes devisible by (3). so when we add (3) after we add 1 it becoms devisable by (3) again Hence ,there is no prime will be (except 2 ) Try This : Suppose( 2+0=x ) ,( x+1=y ), y+3=z , where (x,y,z are sum of the digits of the numbers)

Whenever you add $0$ or $2$ the number will be divisible by $2$ , and whenever you add $1$ or $3$ it will be divisible by $3$ . So, only the first number $2$ is a prime number.