Seemingly easy!!

Algebra Level 3

Let a , b , c a,b,c be positive integers such that b a \frac{b}{a} is an integer. If a , b , c a,b,c are in geometric progression and the arithmetic mean of a , b , c a,b,c is b + 2 , b+2, find the value of

a 2 + a − 14 a + 1 . \dfrac{a^2+a-14}{a+1}.


The answer is 4.

View wiki
Parth Lohomi by Parth Lohomi , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Here is my solusion

12 Helpful 1 Interesting 0 Brilliant 2 Confused
Shivam Hinduja
Dec 19, 2014

The question is wrong , there is a typo in the question. There should have been

a^{2} + a -14 (which is the real IIT JEE question)

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Thanks, I have updated the question.

In future, if you spot any errors with a problem, you can “report” it by selecting the “dot dot dot” menu in the lower right corner. You will get a more timely response that way.

Calvin Lin Staff - 6 years, 5 months ago

I reported it .

Shubhendra Singh - 6 years, 5 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...