Select n n from 2 n 2n

In how many ways can we select n n objects from a collection of size 2 n 2n that consists of n n distinct and n n identical objects?

2 n 2^n ( 2 n ) ! n ! \frac{(2n)!}{n!} n ! n! ( 2 n n ) \binom{2n}{n}

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1 solution

Brian Lie
Mar 17, 2021

We can select k k objects from the collection of n n distinct objects and n k n-k objects from the collection of n n identical objects in ( n k ) \binom{n}{k} ways, making the answer k = 0 n ( n k ) = 2 n . \sum_{k=0}^n\binom{n}{k}=2^n.

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