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Algebra Level 4

Calculate the minimum value of the following expression if { a 1 , a 2 , a 3 , a 4 , a 5 , a 6 } = { 1 ; 2 ; 3 ; 4 ; 5 ; 6 } \{a_1, a_2, a_3, a_4, a_5, a_6\} = \{1; 2; 3; 4; 5; 6\} .

( a 1 + a 2 + a 3 ) ( a 3 + a 4 + a 5 ) ( a 5 + a 6 + a 1 ) \large (a_1 + a_2 + a_3)(a_3 + a_4 + a_5)(a_5 + a_6 + a_1)


The answer is 693.

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1 solution

X X
Feb 8, 2019

The sum of the three brackets is 2 ( a 1 + a 3 + a 5 ) + a 2 + a 4 + a 6 2(a_1+a_3+a_5)+a_2+a_4+a_6

Let the sum be the smallest. So let a 1 = 1 , a 3 = 2 , a 5 = 3 a_1=1,a_3=2,a_5=3

The product becomes ( 3 + a 2 ) ( 5 + a 4 ) ( 4 + a 6 ) (3+a_2)(5+a_4)(4+a_6)

The sum of the brackets is constant( = 27 =27 )

Let gaps of the values of each bracket be bigger, so the output would be smaller.

Hence let a 2 = 4 , a 4 = 6 , a 6 = 5 a_2=4,a_4=6,a_6=5 . The product becomes 693.

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