This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Sum of geometric progression with infinitely many terms.
a = 0 . 4 5 , r = 0 . 4 5 0 . 0 0 4 5 = 0 . 0 0 4 5 0 . 0 0 0 0 4 5 = 0 . 0 1
S = 1 − r a = 1 − 0 . 0 1 = 0 . 4 5 4 5 4 5 4 5 0 . 4 5
Problem Loading...
Note Loading...
Set Loading...
The sequence can be added like this,
0 . 4 5 + 0 . 0 0 4 5 + 0 . 0 0 0 0 4 5 + 0 . 0 0 0 0 0 0 4 5 + 0 . 0 0 0 0 0 0 0 0 4 5
This will invariably result in a sum equal to 0 . 4 5 4 5 4 5 4 5 4 5 4 5 4 5 4 5 4 5 . . . .