Sequence

Algebra Level 1

{ 4 , 9 , 16 , 25 , … } \{4,9,16,25,\ldots\}

Find an equation for the terms of the sequence.

(n-1)^2 1+(3+(2*(n-1))) n^3 (n+1)^2

Mohamed Mamdouh by Mohamed mamdouh , 25, Egypt

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3 solutions

Mohamed Mamdouh
Jun 2, 2014

This problem has two solutions (n+1)^2 and 1+(3+(2*(n-1))) however they will give a different sloution after a certain n

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Nikhil Raj
May 30, 2017

a 1 = ( 1 + 1 ) 2 a 2 = ( 2 + 1 ) 2 a 3 = ( 3 + 1 ) 2 a 4 = ( 4 + 1 ) 2 S o , a n = ( n + 1 ) 2 \begin{aligned} a_1 = (1 + 1)^{2} \\ a_2 = (2 + 1)^{2} \\ a_3 = (3 + 1)^{2} \\ a_4 = (4 + 1)^{2} \\ So, a_n = (n + 1)^{2} \end{aligned}

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Bharath Spidy
Jul 3, 2014

Given sequence is { 4, 9, 16, 25 },

Lets take the sequence from the value 1

(1+1)^2 = 4,

(2+1)^2 = 9,

(3+1)^2 = 16,

(4+1)^2 = 25

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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