calculate 1/3+1/5+1/7+1/9+1/11+1/33+1/35++1/45+1/55+1/77+1/105
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Ron Grahan taught us that any number bigger than 77 that can be represented as the sum of different integers has as the result of the sum of each reciprocal of the integers equals to one (1). 1/3+1/5+1/7+1/9+1/11+1/33+1/35+1/45+1/55+1/77+1/105 = 1, if 3+5+7+9+11+33+35+45+55+77+105 > 77. Now I want a better mathematician to explain 'why'.