Sequence and series (g.p) que no 69

Sum of $n$ terms of a G.P. series whose first term is $a$ and common ratio $r>1$ is $\dfrac{a(r^n-1)}{r-1}$ . Here $a=\dfrac{1}{\sqrt 3}$ and $r=\sqrt 3$ . So, the sum is $\dfrac{19682}{\sqrt 3\times (\sqrt 3-1)}=\boxed {\dfrac{9841(\sqrt 3+1)}{\sqrt 3}}$