Find the missing term-
2, 10, 26, 50, ?
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in Algebra form basically:
(a1 ),(a2),(a3),(a4),(a5),(an)
a1, a1 + r, a2 + 2r, a3+3r, a4+4r... an+nr
Whereas:
a1 = 2
r = 8
n = unknown
**EDIT Lol, this isn't really the solution but rather the formula for the problem :D 99% legit
An n term can be calculated by- ( 2 n − 1 ) 2 + 1
The sequence is regular in that if I subtract 2 from each number, then 0, 8, 24, 48, ⋯ .
So, we can find it easily.
The difference between each consecutive number is all the multiply of eight, so we can define it.
8 n = 3 2 ⇒ n = 4 .
So, 50 + 32 = 8 2 .
add multiples of 8 to every number i.e 2 + 1X8 = 10, 10 + 2X8 = 26, 26 + 3X8 = 50, 50 + 4X8 = 82
The sequence is: 2, 10, 26, 50, ?
We can visualize the pattern like:
2+8*0 = 2
2+8*1 = 10
10+8*2 = 26
26+8*3 = 50
50+8*4 = 82
Therefore, the answer is 82
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The difference between 10 and 2 is 8
Difference between 26 and 10 is 16
Difference between 50 and 26 is 24
From the above sequence, we can say that the difference between the consecutive term is consecutive natural multiple of 8
Therefore the missing term is 50+32=82