n = 1 ∑ ∞ n 2 ( n + 1 ) 2 2 n + 1 = 4 3 + 3 6 5 + 1 4 4 7 + 4 0 0 9 ⋯ = ?
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Hey , what is that greek letter called? By the way nice solution
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No thats not a greek letter :-)......... Use \mathfrak{S} for that....
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S = n = 1 ∑ ∞ ( n 2 ( n + 1 ) 2 2 n + 1 )
S = n = 1 ∑ ∞ ( n 2 ( n + 1 ) 2 ( n + 1 ) 2 − n 2 ) = n = 1 ∑ ∞ ( n 2 1 − ( n + 1 ) 2 1 )
( A T e l e s c o p i c S e r i e s )
= 1 2 1 − 2 2 1 + 2 2 1 − 3 2 1 + 3 2 1 ⋯
= 1 2 1 = 1