An algebra problem by Munem Shahriar

Algebra Level 2

5 , 8 , 11 , 14 , ⋯ \large 5, 8, 11, 14, \cdots The above shows the first few terms of an arithmetic progression . If 2018 is the n th n^\text{th} term of this progression, find n n .


The answer is 672.

Munem Shahriar by Munem Shahriar , 18, Bangladesh

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1 solution

Munem Shahriar
Jan 8, 2018

a + ( n − 1 ) d = nth term a +(n-1) d = \text{nth term}

5 + ( n − 1 ) 3 = 2018 5+(n-1)3 = 2018

5 + 3 n − 3 = 2018 5+3n-3 = 2018

5 + 3 n = 2021 5+3n = 2021

3 n = 2016 3n = 2016

n = 672 n = \boxed{672}

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