Set of complex numbers with a property

Algebra Level pending

let A = { a + i b a , b Z } A=\{a+ib \big|a,b \in Z\} . Here i = 1 i=\sqrt{-1} is a imaginary unit. U = { x A 1 x A } U=\{x\in A \big| \frac{1}{x} \in A\} . find the number of elements in U U .


The answer is 4.

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1 solution

let x = a + b i x=a+bi be a complex number 1 x = 1 a + i b = a i b a 2 + b 2 \frac{1}{x}=\frac{1}{a+ib} = \frac{a-ib}{a^{2}+b^{2}} , now denominator is equal to one and a Z a\in Z and b Z b\in Z is the sufficient and necessary condition for this question. the solutions are ( a , b ) \big(a,b\big) \in { ( 0 , 1 ) , ( 1 , 0 ) , ( 1 , 0 ) , ( 0 , 1 ) } \{\big(0,1\big),\big(1,0\big),\big(-1,0\big),\big(0,-1\big)\} there are only four solutions.

You should write a , b Z a,b\in Z in the question.

Shikhar Srivastava - 1 year, 1 month ago

thank you . I changed it

A Former Brilliant Member - 1 year, 1 month ago

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