Number of students who have opted for subjects A,B and C are 60,84,108 respectively .
The examination is to be conducted for these students such that only the students of the same subjects are allowed in one room . Also the number of students in each room must be the same .
What is the minimum number of rooms that should be arranged to meet these conditions
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We need to find the highest common factor of 60, 84 and 108 - this will be the number of people in each room. This number, after a little prime factorisation, turns out to be 12.
Therefore, we need 5 rooms for the students studying A, 7 for B, and 9 for C.
9 + 5 + 7 = 2 1