Seven Ate Nine

Algebra Level 1

1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 1,\ 2,\ 3,\ 4,\ 5,\ 6,\ 7,\ 8

Eliminate one number from the list above such that the sum of all numbers before the eliminated number is equal to the sum of all numbers after that.

What is the eliminated number?

7 6 4 5

Pi Han Goh by Pi Han Goh , 30, Malaysia

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2 solutions

Jordan Cahn
Dec 10, 2018

1 + 2 + 3 + 4 + 5 = 15 = 7 + 8 1+2+3+4+5 = 15 = 7+8

3 Helpful 0 Interesting 0 Brilliant 0 Confused
B D
Dec 23, 2018

1 ≠ 33 = 3 + 4 + 5 + 6 + 7 + 8 1 \not = 33 = 3 + 4 + 5 + 6 + 7 + 8 2 is eliminated. 1 + 2 = 3 ≠ 30 = 4 + 5 + 6 + 7 + 8 1 + 2 = 3 \not = 30 = 4 + 5 + 6 + 7 + 8 3 is eliminated. 1 + 2 + 3 = 6 ≠ 26 = 5 + 6 + 7 + 8 1 + 2 + 3 = 6 \not = 26 = 5 + 6 + 7 + 8 4 is eliminated. 1 + 2 + 3 + 4 = 10 ≠ 21 = 6 + 7 + 8 1 + 2 + 3 + 4 = 10 \not = 21 = 6 + 7 + 8 5 is eliminated. 1 + 2 + 3 + 4 + 5 = 15 = 15 = 7 + 8 1 + 2 + 3 + 4 + 5 = 15 = 15 = 7 + 8 6 is eliminated. 1 + 2 + 3 + 4 + 5 + 6 = 21 ≠ 8 1 + 2 + 3 + 4 + 5 + 6 = 21 \not = 8 7 is eliminated.

1 Helpful 0 Interesting 0 Brilliant 0 Confused

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