Seven Eight Nine

Logic Level 3

E I G H T N I N E + T E N S E V E N \begin{array}{ c c c c c c } & \text{E} & \text{I} & \text{G} & \text{H} & \text{T} \\ & & \text{N} & \text{I} & \text{N} & \text{E} \\ + & & & \text{T} & \text{E} & \text{N} \\ \hline & \text{S} & \text{E} & \text{V} & \text{E} & \text{N} \\ \end{array}

Solve the cryptarithm above, and find E + I + G + H + T + N + S + V E + I + G + H + T + N + S + V .


The answer is 35.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Mohtasim Nakib
May 11, 2015

my way of solution is a little boring.

T + E + N = N so T + E = 10 . there are (T,E)=(1,9),(9,1),(2,8),(8,2),(3,7),(7,3),(4,6),(6,4) possible pairs.

H+N+E+1 = E so H+N+1 =10 , H+N =9 . there are (H,N)=(1,8),(8,1),(2,7),(7,2),(3,6),(6,3),(4,5),(5,4) possible pairs.

and E+1=S.

starting by taking possible pair of(H,N) and attempting each pair I find

27058+4742+ 824=32624

so the ans is:

2+7+0+5+8+4+3+6 = 35

close to mine, from those equations you can also know that 1<E<9 and E=I+N-9, helping to asume that E is a low value,

Jesus Frankenstein - 6 years, 1 month ago

Sir, I'm admiring you how you got it, for me, I think even I solve it the whole day I cannot arrive at the answer. I have only some inquiry on your solution, at first, how did you know that (T,E) = (1,9), isn't the 10 has many additives, like (3,7), (2,8), (6,4) and so on, or It can also be (0,0), for the N to retain, then how did you know that these are 1 and 9, and the same also for other letters/variables. thank you sir and I'm hoping for your response.(:

Hubert Hernandez Jr. - 6 years, 1 month ago

Log in to reply

its more a try and see than an straight method what you need to solve this problem; i remember a couple of those deductions: eache letter is a number from 0 to 9 no letter has the same value than another since E+T=10 and E cannot be equal to T E and T cant be 0 or 5 making T be a function of E: T=10-E S=E+1, since S<10, E+1<10; E<9 and you know that I+N+ (highly possible) 1 = E + 10, (otherwhise the last addition would give another E instead of an S) since E cant be 0, I+N NEED to be bigger than 9

if you check the convinations of different numbers that are true and no number is repeated, youll see that it get higher probabilities for lower values

for example: if (I,N) where (8,9) or (9,8), the value for E would be 8, repeating the number, making false that E=8, now you got one less value to check and if you follow this way to check, end up "seeing" that there are more chances for E to be a low value, the rest is solved like a sudoku

Jesus Frankenstein - 6 years, 1 month ago

since T not equal to E it cant take value (0,0)

Arun Paul - 6 years, 1 month ago

I think you should read that line carefully I have written all the possible additives of (T,E) . :)

Mohtasim Nakib - 6 years, 1 month ago

Log in to reply

thank you sir, what I can't understand is how you arrived at that number(1,9). thank you to Mr. Frankenstein, he elaborated it to me, though, still, it's hard for me to solve the problem like that if I encountered another one. (;

Hubert Hernandez Jr. - 6 years, 1 month ago

Mr Mohtasim Nakib what are the numbers 27058,4742,824,32624 Represent and how did you figure it out ,could you please explain it to me ?

Yousef Mahran - 5 years, 4 months ago

Log in to reply

27058 is the top number (EIGHT), 4742 is the second one (NINE), 824 is the third one (TEN) and 32624 is the sum (SEVEN)

Lu-Uy Hoang - 3 years, 4 months ago

T+E+N=N then how is T+E=10??? I didn't get that. Can you please explain? If cancellation can be applied then it must be T+E=0. Correct me if I'm wrong

Kamal M S - 5 years, 2 months ago

Log in to reply

Think of T+E+N as x+y+z. Since x+y+z=z we subtract z from both sides. This leaves us with x+y=0. In this scenario the only way to achieve 0 in the ones column is to get some multiple of 10. Given only two integers the only possible outcome that can be a multiple of ten is ten, therefore we know that T+E must equal 10.

Andrew Higginson - 5 years, 2 months ago

How can u be sure that T+E=10, it can be a multiple of 10. Please elaborate why u assume that. I know this type of problem can be solve by taking such assumption, but is there any other generic way to solve this problem.

Suraj Aggarwal - 6 years ago

Log in to reply

first thing: each letter has a decimal value and none can be repeted; therefore

T,E,N <10

as a fact, the addition T+E+N < 30, and since no value can be repeated, picking the bigger ones give's you the maximum limit: 9+8+7=24; so

T+E+N < 24

since T+E+N=N and a value to carry(0.1 or 2): you make 3 assumptions:

1) T+E=0. Since T=/=E, so T+E>0

2) if the carry is equal 2, T+E=20, but since T,E <10, the maximum value of T+E=17

3) because the other options are out of the limits / conditions, the only viable option is E+T=10

Jesus Frankenstein - 6 years ago

But a letter can represent a single digit only. So, it should be 10.

srinivas vankayalapati - 5 years, 4 months ago
Paola Ramírez
May 10, 2015

It took me 45 45 minutes solve the cryptarithm E = 2 , I = 7 , G = 0 , H = 5 , T = 8 , N = 4 , S = 3 , V = 6 E=2, I=7,G=0,H=5,T=8,N=4,S=3,V=6

E + I + G + H + T + N + S + V = 35 E + I + G + H + T + N + S + V=\boxed{35}

Please post ur method!!

Adarsh Kumar - 6 years, 1 month ago

How you got that ? explain me please :D

Dark's Matter - 6 years, 1 month ago

Hey Paola, could u tell me about ur approach to solve that problem. Very thankful to u in advanced.

Suraj Aggarwal - 6 years ago

tbh, I just guessed.

Adain Luckadue - 5 years, 7 months ago

Hey Paola can u please tell me, from where did u come to know the values of alfabets??...

Sanket Bhange - 4 years, 8 months ago

pls say how ?

Rahul thachil - 4 years, 5 months ago

Why this isn't the solution of the cryptarithm...

  1. Where..
      1. E=8. I=1. G=4. H=2. T=2.
      1. N=7. S=8. V=8.

  1. ?????????

Yash Parekh - 1 year, 10 months ago
Lu Chee Ket
Nov 11, 2015

The equation is 10000 S + 100 V = 9001 E + 1100 I + 1010 N + 101 T + 100 G + 10 H;

27058

4742

824

32624

2 + 7 + 0 + 5 + 8 + 4 + 3 + 6 = 35

Mr Lu i understand how did this equation mean but what are the numbers 27058,4742,824,32624 Represent and how did you figure it out ,could you please explain it ?

Yousef Mahran - 5 years, 4 months ago
Ελιά Ο.Β.
Oct 17, 2016

I decided to try to solve this problem by finding what where the 3 digits that weren't in the cryptarithm and deduced that neither 0, 9 or 1 could be used in the problem. Went rapidly as those where the obvious firsts digits to try.

I can not follow your line of reasoning, especially since 0 is in the cryptarithm...

Karen Mulders - 3 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...