A three digit number is formed by throwing a fair dice three times. If m out of n times the number so obtained is divisible by 7, then m + n equals: (m and n are relatively prime)
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can u please explain the method , I got 216 as the possible numbers formed but what to do next?
There are 2 1 6 total possibilities. Then we must find all numbers from 1 0 0 − 6 6 6 that are divisible by 7 and contain digits 1 − 6 only, which turn out to be 3 0 . { 1 6 1 , 2 3 1 , 4 4 1 , 5 1 1 , 6 5 1 and so on,note that when u fix the last digit, the other two digits will be a part of an AP, so you can calculate easily.}
Thus the required probability is 2 1 6 3 0 = 3 6 5 and the required answer is 5 + 3 6 = 4 1
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There are 216 possible numbers formed, and through some math, and or program, it turns out that 30 of those are divisible by 7. 30/216 = 5/36, 5+36 =41.