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Applying Similarity of Triangle, get result... :D
consider x is length of shadow S+x is total length of shadow end to the buiding 6x(S+x)=20x
Let us consider the shadow length = x
The 6 feet person is standing S feet away from the building.
20/(S+x) = 6/x
By solving the above equation you get x = 3S/7
Or let the angle between the light ans the building is Theta, and the length of shadow is x, then
tan θ = 2 0 X + S = 1 4 S
Then 14(X+S) = 20S
X = 7 3 S
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let Shadow length = A then,
6/A=20/(A+S)
so... A=3/7*S