Shakes

Probability Level 1

6 people attended a meeting. If all guests shook hands with everyone (no pair shook hands more than once), how many handshaking events were there?


The answer is 15.

Ritu Roy by Ritu Roy , 22, India

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7 solutions

Ryan Redz
Jun 5, 2014

n(n-1)/2 = 6(5)/2 = 15

6 Helpful 0 Interesting 0 Brilliant 0 Confused
Ritu Roy
May 14, 2014

15 handshhakes. The first person would have shaken hands 5 times. The second, 4 times and so on. Thus, 5+4+3+2+1=15

4 Helpful 0 Interesting 0 Brilliant 0 Confused
Galen Buhain
Mar 25, 2017

n(n-1)/2 =hand shales,we subsitute for n+6 so answer is 15

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Krishna Garg
Jul 20, 2014

applying the corelation n(n-1)/2 =hand shales,we subsitute for n+6 so answer is 15. K.K.GARG,India

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Nithila Sivakumar
Jun 25, 2014

just use the formula n(n-1)/2 n=6 6(5)/2 =15

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(6*5)/2=15

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Hello yo,

Total handshaking events = 6C2 = 15....

Thanks....

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