Every body in a room shakes hand with every body else. The total number of handshakes that occur is 66. The total no. of persons in the room is
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great solution but do you know the concept behind this formula?
if there are only 3 people the number of shake hands is 6 and if try to arrive the same figure as per your formula it will be only one shake hand. Request your clarification on the same
I'm pretty sure that there is another question just like this with the same answer and everything.
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yes, I too think that. Many people have posted this kind of question
With 1 person you cant shake hands. With 2 persons you have 1 shake (1). With 3 persons you have 3 shakes (1+2). With 4 persons you have 6 shakes (1+2+3). With 5 persons you have 10 shakes (1+2+3+4). With 6 persons you have 15 shakes (1+2+3+4+5). With 7 persons you have 21 shakes (1+2+3+4+5+6). With 8 persons you have 28 shakes (1+2+3+4+5+6+7). With 9 persons you have 36 shakes (1+2+3+4+5+6+7+8). With 10 persons you have 45 shakes (1+2+3+4+5+6+7+8+9). With 11 persons you have 55 shakes (1+2+3+4+5+6+7+8+9+10). With 12 persons you have 66 shakes (1+2+3+4+5+6+7+8+9+10+11). So there are 12 persons.
Of course you can do N persons have x shakes. So N+1 persons have x+N shakes.
If there are n man, and it takes 2 man for a handshake.
So, ( 2 n ) = 6 6
( n − 2 ) ! ( 2 ) ! n ! = 6 6
n ( n − 1 ) = 1 3 2
n 2 − n − 1 3 2 = 0
n 2 − 1 2 n + 1 1 n − 1 3 2 = 0
( n − 1 2 ) ( n + 1 1 ) = 0
So, the value of n is either 1 2 , − 1 1 .
Number of person can not be negative so number of person is 1 2
1 person=0 ; 2 person=1 ; 3 person=3 ; 4 person=6 the equation 1/2 n^2 - 1/2 n = 66 (factorized it) n =12
The formula for such type of questions is (n-1)(n-2)/2 where n is the number of values...in this case...we need to find n-1...equation formed = (n-1)(n-2)/2 = 66
(n-1)(n-2)=132, solving the quadratic equation, we get n =13...and n-1 = 12
For any given amount of people p , the formula for the number of possible handshakes is 2 p ( p − 1 ) . Setting this equal to 66, we find that p = 1 2 .
to add nick's solution, for 5 person, hand shakes are (4+3+2+1 i.e. (5-1)!). similarly for 6 person, it would be (6-1)! or we can say 5! hand shakes are for 6 person. Similarly for n! handshakes, no. of persons would be (n+1). If n is natural number, n! = n x (n+1)/2, therefore, 65 handshakes means 65 = n! = n x (n+1)/2 = 11. So total persons would be (n+1) i.e. 12.
that's 12C2 = nC2 = 66 n = 12
assume total person in room is n then total hand shaking is n(n-1)/2 so n(n-1)/2=66 from this equation n=12
12! / (12-2)! * 2
12! / 10! * 2
(12 *11) / 2
6 * 11
66
Total number of shake hands, total number of lines drawn by joining given points, total number of angles in the figure is given by the formula n(n – 1)/2
where n is number of persons, number of dots or points and number of rays drawn from one origin
n(n – 1)/2 = 66 then n(n – 1) = 132 so number of persons n = 12
n*(n-1)/2=66.....on solving this we get n=12
why do we take the formula till n(n-1)/2, and why no continue it to n(n-1) (n-2)/6 and so on
When there are n+1 people shaking hands with every other person, the total number of handshakes would be (n+1)*n/2. Equating this to 66, we get n+1=12
the combination for total no of hand shake is nc2 since each hand shake involve 2 person and hence on solving it came n =12 .
its combination... the no. of handshakes among n people is nC2=n!/(n-2)!2! =n(n-1)/2
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The formula for such type of questions is (n-1)(n-2)/2 where n is the number of values...in this case...we need to find n-1...equation formed = (n-1)(n-2)/2 = 66
(n-1)(n-2)=132, solving the quadratic equation, we get n =13...and n-1 = 12