Four equal ,equilateral triangles of side 1cm is joined together to form parallelogram. Find the length of its longest diagonal in this parallelogram.
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If all the triangles are arranged to form a parallelogram then the largest angle formed will be of 120 degree= 60+60 Therefore by applying the cosine rule we will have the answer as follows (digonal )square= (1st side) square+(2nd side) square - 2 S1 S2*cos120