There are 2 congruent triangles, each measuring 6 meters in height and 5 meters in width. The two triangles are placed in such a way they overlap with their bases over each other. Find the area of their overlapping area.
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The highest point in the overlapping area is where the two hypotenuses meet. Their intersection is exactly half of the height of the triangle. The base of the overlapping area is the same of the base of a single triangle. With all this information, we can finally compute for the area.
A = (bh)/2
A = [(5 m)(3 m)]/2
A = (15 sq. m) /2
A = 7.5 sq. m