Shed the limit

Calculus Level 1

$\large \lim_{n \to \infty }~ \dfrac{n+2}{n+3}= \, ?$

1 0

\dfrac{5}{4}

\infty

1 solution

Shivam Jadhav
Jan 23, 2016

$\lim_{n\to\infty}\frac{n+2}{n+3}$ $\boxed{=\lim_{n\to\infty}\frac{1+\frac{2}{n}}{1+\frac{3}{n}}=1}$ $since,\lim_{n\to\infty}\frac{1}{n}=0$ .