sheepy

Algebra Level 3

2 brothers had a flock of sheep. they sold the flock and got as many rupees for every sheep as was the number of the sheep in the flock =. the money was shared in the following way: first, the elder brother took 10 rupees, then the younger brother, after which elder brother took 10 rupees again, and so on. finally, it turned out that at the last stage when it was the younger brother's turn to take money there remained less than 10 rupees. therefore the younger brother took the rest of the money and the elder bother gave him his knife for the sharing to be fair. Find the cost of the knife

8 2 3 9 7 1 4 5

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1 solution

Azadali Jivani
Jun 7, 2017

Suppose total no. of seeps = x
Price of each sheep = x
Total amount = x^2
6^2 = 36
Elder brother received 10 + 10 = 20
Younger received = 10 + 6 = 16 [ younger brother received 4 less, if elder broth. give him Rs.2 then distribution become equal
So the price of knife = Rs.2
Note; except 6 no other no. is possible

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