Shifting the numbers, part 2

Logic Level 5

A B C D E F C D E F A B = n n + 5 \frac{\overline{ABCDEF}}{\overline{CDEFAB}}=\frac{n}{n+5}

What is the sum of all positive integers n < 100 n <100 such that there exist a solution for the 6-digit number A B C D E F \overline{ABCDEF} ?

Example : n = 12 n=12 is possible and you may try a related problem here .


This question is part of the set Shifting the numbers .


The answer is 146.

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1 solution

Francis Kong
Nov 11, 2017
A B C D E F \overline{ABCDEF} A B C D E F / C D E F A B \overline{ABCDEF}/\overline{CDEFAB} n n
131868 131868 12 17 \frac{12}{17} 12
142857 142857 1 2 \frac{1}{2} 5
162162 162162 3 4 \frac{3}{4} 15
384615 384615 5 6 \frac{5}{6} 25
343629 343629 89 94 \frac{89}{94} 89

Total is

12 + 5 + 15 + 25 + 89 = 146 12+5+15+25+89 = \boxed{146}

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