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Geometry Level pending

ABCD is a square. Given that AB is 6 cm and triangles ABF and CED are equilateral. Find the length of EF exactly. And then give your answer to 4.sf.


The answer is 4.392.

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1 solution

Consider right F G B \triangle FGB . Applying the theorem of Pythagoras, we have, G F = 6 2 3 2 = 3 3 GF=\sqrt{6^2-3^2}=3\sqrt{3} . Therefore the length of E F EF to four significant figures is

E F = 2 ( 3 3 ) 6 4.392 EF=2(3\sqrt{3})-6\approx \color{#D61F06}\boxed{4.392}

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