Shipping

A merchant can place 8 large boxes or 10 small boxes into a carton for shipping. In one shipment, he sent a total of 96 boxes. If there are more large boxes than small boxes and the merchant must ship at least one small box, then how many cartons did he ship?


The answer is 11.

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3 solutions

Parveen Soni
Nov 19, 2014

Since we have 96 boxes and no. of big boxes >no. of small boxes ------(1)
Also there are some big boxes and small boxes. -------(2)
So no. of big boxes=multiple of 8
no. of small boxes=multiple of 10 (always result last digit as 0)
As per above facts, to have total 96 boxes we must have a multiple of 8 that have last digit as 6 which are 16 and 56 and 96.
If big boxes cartons are 2 (16 boxes) then small are of 8 (80 small boxes) --(3)
If big boxes cartons are 7 (56 boxes) then small are of 4 (40 small boxes) --(4)
If big boxes cartons are 12 (96 boxes) then small are of 0 (0 small boxes)---(5)
only (4) satisfy (1) and (2).
Hence total no. of cartons=7(big)+4(small)=11


11 cartons total is the answer as:

7 large boxes (7 * 8 = 56 boxes)

4 small boxes (4*10 = 40 boxes )

11 total cartons and 96 boxes

Siddharth Singh
Dec 1, 2014

8x+10y=96. x>y, x=7 and y=4. Other values cannot be possible

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