SHM - 2
A particle oscillating in simple harmonic motion has its motion timed at when it is at the mark. It travels between the and marks with a period of . Where is the position of the particle at time ?
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1 solution
The equilibrium position is at the 60 cm mark. The +ve is to the right of the 60 cm mark, the -ve is to the left. Since timing begins at the amplitude position (the 50 cm mark),
x = − x o c o s [ T 2 π t ])
x = − ( 1 0 ) c o s [ 2 ( 2 π ) ( 0 . 7 5 ) ])
x = 7.1
x = 7.1 corresponds to the 67.1 cm mark.