SHM problem

Classical Mechanics Level 3

A pendulum with length of 36. 9 cm had a period of 1. 22 sec. What is the acceleration in $\text{ m/s}^2$ due to gravity at the pendulum's location?

Give your answer to three decimal places

1 solution

Akshat Sharda
Mar 22, 2016

Time period $(T)$ of a simple pendulum is,

$T=2\pi \sqrt{ \frac{l}{g} }$

Where $l$ is length in meters and $g$ is acceeleration due to gravity meter per second square.

$1.22=2\pi \sqrt{ \frac{0.369}{g} } \\ g=\frac{ (2\pi)^20.369}{(1.22)^2}= \boxed{9.787}$