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Two masses m 1 m_1 and m 2 m_2 are both held by two separate strings. Thus, there were two separate simple pendulums. The first mass takes twice as long to complete one swing (small angle oscillation), as compared to that of the second mass.

What are the ratio of the two masses m 1 m 2 \frac{m_1}{m_2} ?

Details and Assumptions

  • The acceleration due to gravity is g = 9.81 m s 2 g = 9.81 \frac{m}{s^2} .

  • Treat both as point masses. Neglect the masses of the strings.

  • Both mass are under the influence of Earth's gravity.

  • Both mass are at the same distance from the Earth's center.

  • Neglect other forces such as friction, drag, etc. The systems are ideal ones.

2 1 2 \frac{1}{2} 1 The data given was insufficient.

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1 solution

Shikhar Bhardwaj
Mar 15, 2014

It is said that both the masses are at the same distance from the center of the earth. But this by no way means that that the masses are at the same distance from their respective points of suspension. We have got no idea of the length of the string of the two pendulum systems. So the data given is insufficient.

I thought that...but then i assumed that when it said at equal distance from centre of earth.....got confused and marked the ratio 1:1....silly!!

Tanya Gupta - 7 years, 2 months ago

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