Resistors in Series and in Parallel

Ten resistors, each having a resistance of 120 Ω 120 \Omega , are arranged as shown above. Find the total resistance.

100 200 250 150

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1 solution

Rishabh Jain
Feb 17, 2016

R 1 S ( R 2 P R 3 ) S ( R 4 P R 5 P R 6 ) S ( R 7 P R 8 P R 9 P R 10 ) \color{#D61F06}{R_1\color{#20A900}{S}(R_2\color{#3D99F6}{P}R_3)\color{#20A900}{S}(R_4\color{#3D99F6}{P}R_5\color{#3D99F6}{P}R_6)\color{#20A900}{S}(R_7\color{#3D99F6}{P}R_8\color{#3D99F6}{P}R_9\color{#3D99F6}{P}R_{10}}) where 'S' denotes Series and 'P' denotes parallel) = R + R 2 + R 3 + R 4 =R+\dfrac{R}{2}+\dfrac{R}{3}+\dfrac{R}{4} = 25 R 12 = 250 =\dfrac{25R}{12}=\boxed{250}

Maybe you can denote it as -

R 1 + R 2 R 3 + R 4 R 5 R 6 + R 7 R 8 R 9 R 10 R_{1}+ R_{2}|| R_{3}+ R_{4}|| R_{5}|| R_{6}+ R_{7}|| R_{8}|| R_{9}|| R_{10}

Akshat Sharda - 5 years, 3 months ago

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